ࡱ> ]_\wq` bjbjqPqP ::2222222F****Dn\F$$$$$$$$%h(F$2c"$22$-!-!-! 22$-!$-!-!22-! з^ *-!!$0$-!b(A b(-!b(2-!-!$$#! $FFF*FFF*FFF222222  E J E R C I C I O S D E M A T E M T I C A S 1.- Traduce al lenguaje algebraico los siguientes enunciados: 1.-La suma de un nmero n y su mitad 7.-El triple de la mitad de un nmero n 2.-El siguiente de un nmero n 8.-El anterior a un nmero n 3.-El cudruplo de un nmero n mas dos 9.-La terceras parte de un nmero n menos cinco 4.-El doble de un nmero n ms su mitad 10.-El doble de un nmero n menos tres unidades 5.-Un nmero ms su mitad ms su tercera parte 11.-En triple de un nmero n ms seis 6.- La mitad de un nmero n menos cuatro 12.- El rea de un rectngulo de base a y altura b 13.-En Una divisin, el dividendo es igual al divisor por el cociente ms el resto. 14.-El orden de los factores (a y b) no altera el resultado del producto. 15.-En una divisin (a : b),si multiplicamos el dividendo y el divisor por un mismo nmero(c) el resultado de la divisin no varia. 16 El orden de los sumandos ( a y b) no altera el resultado de la suma. 17.-En una resta (a b= c), si sumamos el sustraendo y la diferencia, el resultado es el minuendo. 18.-El rea S de un tringulo es igual a la mitad del producto de la base (b) por la altura (a). 19.-El permetro P, de un rectngulo de base b y altura a. 2.-Calcula el valor numrico del polinomio para los valores que se indican: 3x2 3x + 6 2x4 + 3x3 2x2 6x2 + 3x 2 a) Para x = -1 a) Para x = -2 a) Para x = 2 b) Para x = 3 b) Para x = 1 b) Para x = -3 3 Considera los polinomios A , B y C y calcula A + B y B - C A= 3x2 + 5x - 6 A = 5x2 - 2x + 4 A= 5x2 + 2x 9 B= 2x4 2x3 + 4x 2 B = 3x4 + 5x3 4x2 + 2x 2 B= 5x4 3x3 +4x2 + 6x 7 C= x3 + 5x2 2x 3 C= 3x3 - 2x2 - x + 6 C= 6x3 + 4x2 x + 7 A= 2x2 + 9x + 12 A= 6x2 +10x +9 B= 3x4 + 2x3 + 4x2 +2x + 10 B= 12x4 + 6x3 +5x2 -2x + 7 C= 6x3 -2x2 + 3x 8 C= 5x3 + x2 x 5 4.-Calcula: 2x (x3 +3x2 5x + 4) = (x3 + 2x2 5x) 6x = 2x (x3 2x + 5 ) = (x2 + 2 ) (x3 +2x 3 ) = (2x2 3 ) (x3 + 2x2 3x 5) = (3x +2) (3x3 + 4x2 2x 6 ) = (x 4) (2x3 +3x2 2x 6 ) = 4x (3x2 + 2x 5) = 5.-Extraer factor comn en cada una de las siguientes expresiones: 4x2 + 2x = 5x + 5y = 3x2 + 3x = 4x4- 4x3 + 4x2 = 3x3y + 3x2y + 3xy = x3y +x2y +2xy = 6 + 3b = 15x 10y = 6x4 + 3x2 = 8x5 12x3 +4x2 = 6x3 + 12x2y 18xy2 = 6.-Calcular aplicando los productos notables: (x + 1)2 = (2x + 1)2 = (x + 2)2 = (2x y)2 = (x 3)2 =  EMBED Equation.3  (m + 2)(m 2) = (x + 1)(x 1) = (x + 4)(x 4) = (2 + x)2 = (x + 3)2 = (5x + 3)(5x 3) = (3x 1)2 = (x 5)2 = (2x + 3y)(2x 3y) = 7.- Expresa en forma de producto notable: 16x2 + 32x + 16 = x2 + 4xy + 4y2 = x2 + 2x + 1 = 9x2 + 12x + 4 = 4x2 + 8xy + 4y2 = 9x2 12x + 4 = 9x4 12x2 + 4 = x2 6x + 9 = 4x2 4xy + y2 = 4x2 -20x + 25 = 4a2 4b2 = x2 4y2 = x2 1 = 9x2 4y2 = a2 9b2 = 8.- Simplificar las siguientes fracciones:  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  9.-Completar los valores que faltan en las siguientes tablas: n13612n139122n+461220343n-21132837 n23712n238122n+151119292n+37132333 n1511 EMBED Equation.3  1 2 5 10 8 CE  K r t ~ _ ` d !xzɽzzzzzzzsghRh!d5mH sH  hR5H* h!d5H* h!d5 hF5hFhF5hF5CJaJhZV5CJaJhlfhTk5CJaJhlfh 4I5CJaJhFh 4I5CJaJhFh 4I5CJaJh 4I5CJaJh 4Ih 4I5CJaJh3h 4Ijh 4IUmHnHu(DEG H   s t 4 5   Y Z gd 4I$a$gd 4I " # _ ` ,-'(jkU,{|ogd 4I"#>?DEIJabgh"#WX]^cd}~9:?@lmܼܱhIv5mH sH hIv5H*mH sH h!d5mH sH hRh!d5mH sH hR5H*mH sH hR5mH sH hRhR5H*mH sH hRhR5mH sH B+,01]^op%&2378=>jkqr<=CDHIrsyzhC8Ehlf5 hC8E5H* hC8E5 hlf5H* hlf5 ho5hlfhIv5H*hlfhIv5h:hIv5mH sH h:5mH sH hIv5mH sH hIv5H*mH sH ?op./9<=H=>jkgdlf578AB~*EF  GH 89DELµѭ hC8E5H* hz%5H* hz%5 h(5H*h>hlf5h>h>5jhkh(EHUj^RI h(CJUVaJh>jh>U h>5H* h>5 h;M5H* h(5 h;M5 hlf56LMfgmn~349:klܹܡ܉jI h UVjh(h EHUjhI h UVjh(h EHUjI h UVjh(h EHUjI h UVh jh U h 5H* h 5 hz%5 hz%5H*6 !4567ACDWXYZlmö檲zobjh(h&PDEHUj0I h&PDUVj3h(h&PDEHUjזI h&PDUVjh(h&PDEHUjI h&PDUVjh&PDUh&PDj h(h EHUj8I h UVje h(h EHUjI h UVh jh Uj- h(h EHU$k    !"%&',./Ff $$Ifa$gdu9gdlf  "$&',-;?@ACEGIKMNOVWXYZ[\^_acfghijkmnpruyz{}˽˽˸´ hKD5hKDhu95hKDhKD5hKDh hC8E5 h1I5hu9 hu95hu9hu95h&PDh&PD5h&PDjh&PDUjh(h&PDEHUjrI h&PDUV=/2367:;@BCFGJKNOWY[]^`adef $$Ifa$gdKDgdlfFf $$Ifa$gdu9fhjlmopstuz|}Ff4(Ff# $$Ifa$gdKDʽhlfhlf5 h>5h1IhKD5CJaJh1Ih1I5CJaJj+h(hKDEHUjI hKDUVhKDjhKDUhKDhKD5CJaJ h1I5 hKD5hKDhu95 $$Ifa$gdi\gdi\ kdf+$$IfFִ RQPUUUUUUU t06    44 lag  $$Ifa$gdKD kd.$$IfFִ RQPUUUUUUU t06    44 lag gdlf21h:p 4I. 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